What are the solutions to the equation -2x^2+x=-6 ?

The solutions to the equation -2x^2+x=-6 are x=-3/2 ,x=2

Find the zeros of -2x^2+x=-6

The zeros of -2x^2+x=-6 are x=-3/2 ,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} + x = - 6

x = - \frac{3}{2}, x = 2

Decimal Notation

x = - 1.5, x = 2

Solution steps

- 2 x^{2} + x = - 6

Move

6

to the left side

- 2 x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 6 = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 ( - 2 )}, x_{2} = \frac{- 1 - 7}{2 ( - 2 )}

x = \frac{- 1 + 7}{2 ( - 2 )} : - \frac{3}{2}

x = \frac{- 1 - 7}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 2

x^{2} + 2 x + 2

a x^{2} + b x + c

y, x^{2} - y^{2} = 0

\frac{2}{3} x^{2} - 54 = 0

x^{2} - 4 x + 3 = 0

What are the solutions to the equation -2x^2+x=-6 ?
The solutions to the equation -2x^2+x=-6 are x=-3/2 ,x=2
Find the zeros of -2x^2+x=-6
The zeros of -2x^2+x=-6 are x=-3/2 ,x=2