What are the solutions to the equation roots x^2+x+1 ?

The solutions to the equation roots x^2+x+1 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

Find the zeros of roots x^2+x+1

The zeros of roots x^2+x+1 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2

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roots

x^{2} + x + 1

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

Solution steps

x^{2} + x + 1

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 1 : 3 i

x_{1, 2} = \frac{- 1 \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 3 i}{2 \cdot 1}

x = \frac{- 1 + 3 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3}{2}

x = \frac{- 1 - 3 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{3}{2}, x = - \frac{1}{2} - i \frac{3}{2}

x^{2} + 4

x^{2} + 4 x + 5

x, z = x^{2} + y^{2}

x, x^{2} + y^{2} - z^{2} = 1

(x^{2}) + x = 30, x

What are the solutions to the equation roots x^2+x+1 ?
The solutions to the equation roots x^2+x+1 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2
Find the zeros of roots x^2+x+1
The zeros of roots x^2+x+1 are x=-1/2+i(sqrt(3))/2 ,x=-1/2-i(sqrt(3))/2