What are the solutions to the equation 3d^2-9d+3=0 ?

The solutions to the equation 3d^2-9d+3=0 are d=(3+sqrt(5))/2 ,d=(3-sqrt(5))/2

Find the zeros of 3d^2-9d+3=0

The zeros of 3d^2-9d+3=0 are d=(3+sqrt(5))/2 ,d=(3-sqrt(5))/2

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3 d^{2} - 9 d + 3 = 0

d = \frac{3 + 5}{2}, d = \frac{3 - 5}{2}

Decimal Notation

d = 2.61803 \dots, d = 0.38196 \dots

Solution steps

3 d^{2} - 9 d + 3 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 \cdot 3 = 35

d_{1, 2} = \frac{- ( - 9 ) \pm 3 5}{2 \cdot 3}

Separate the solutions

d_{1} = \frac{- ( - 9 ) + 3 5}{2 \cdot 3}, d_{2} = \frac{- ( - 9 ) - 3 5}{2 \cdot 3}

d = \frac{- ( - 9 ) + 3 5}{2 \cdot 3} : \frac{3 + 5}{2}

d = \frac{- ( - 9 ) - 3 5}{2 \cdot 3} : \frac{3 - 5}{2}

The solutions to the quadratic equation are:

d = \frac{3 + 5}{2}, d = \frac{3 - 5}{2}

x^{2} + 9

x^{2} + b x + c

x^{2} + 2 x + 4

x, x^{2} + y^{2} + z^{2} - 4 x + 12 y - 14 z + 40 = 0

y, x^{2} + x y + y^{2} = 1

What are the solutions to the equation 3d^2-9d+3=0 ?
The solutions to the equation 3d^2-9d+3=0 are d=(3+sqrt(5))/2 ,d=(3-sqrt(5))/2
Find the zeros of 3d^2-9d+3=0
The zeros of 3d^2-9d+3=0 are d=(3+sqrt(5))/2 ,d=(3-sqrt(5))/2