What are the solutions to the equation roots x^2+2x+4 ?

The solutions to the equation roots x^2+2x+4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of roots x^2+2x+4

The zeros of roots x^2+2x+4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

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roots

x^{2} + 2 x + 4

x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

x^{2} + 2 x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

x = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

x = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

x = - 1 + 3 i, x = - 1 - 3 i

x, x^{2} + y^{2} + z^{2} - 4 x + 12 y - 14 z + 40 = 0

y, x^{2} + x y + y^{2} = 1

x^{2} - 5 x + 4 = 0

64 x^{2} - (16 a + 4 b) x + ab = 0

14 + 3 h = 5 hh

What are the solutions to the equation roots x^2+2x+4 ?
The solutions to the equation roots x^2+2x+4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of roots x^2+2x+4
The zeros of roots x^2+2x+4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i