What are the solutions to the equation x^2-24x+140=0 ?

The solutions to the equation x^2-24x+140=0 are x=14,x=10

Find the zeros of x^2-24x+140=0

The zeros of x^2-24x+140=0 are x=14,x=10

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x^{2} - 24 x + 140 = 0

x = 14, x = 10

Solution steps

x^{2} - 24 x + 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 140}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 140 = 4

x_{1, 2} = \frac{- ( - 24 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 4}{2 \cdot 1}

x = \frac{- ( - 24 ) + 4}{2 \cdot 1} : 14

x = \frac{- ( - 24 ) - 4}{2 \cdot 1} : 10

The solutions to the quadratic equation are:

x = 14, x = 10

A, A = π r^{2}

y, x^{2} y^{2} = x^{2} + y^{2}

x^{2} + 4 x + 8

x^{2} + 6 x + 10 = - x

2 x^{2} - 20 x + 41

What are the solutions to the equation x^2-24x+140=0 ?
The solutions to the equation x^2-24x+140=0 are x=14,x=10
Find the zeros of x^2-24x+140=0
The zeros of x^2-24x+140=0 are x=14,x=10