What are the solutions to the equation roots x^2+4x+4 ?

The solutions to the equation roots x^2+4x+4 are x=-2

Find the zeros of roots x^2+4x+4

The zeros of roots x^2+4x+4 are x=-2

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roots

x^{2} + 4 x + 4

x = - 2

Solution steps

x^{2} + 4 x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

t, s = u t + \frac{1}{2} a t^{2}

n^{2} + 17 n + 22 = 7

a, c^{2} = a^{2} + b^{2}

4 + 3 x^{2} = 7

- m^{2} + 3 m - 2 = 0

What are the solutions to the equation roots x^2+4x+4 ?
The solutions to the equation roots x^2+4x+4 are x=-2
Find the zeros of roots x^2+4x+4
The zeros of roots x^2+4x+4 are x=-2