What are the solutions to the equation 4+3x^2=7 ?

The solutions to the equation 4+3x^2=7 are x=1,x=-1

Find the zeros of 4+3x^2=7

The zeros of 4+3x^2=7 are x=1,x=-1

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4 + 3 x^{2} = 7

x = 1, x = - 1

Solution steps

4 + 3 x^{2} = 7

Move

4

to the right side

3 x^{2} = 3

Divide both sides by

3

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

- m^{2} + 3 m - 2 = 0

2 x^{2} + (4 b - a) x - 2 ab = 0

x^{2} - 5 x + 6

y, x^{2} + x y + y^{2} = 7

4 - 2 x^{2} = - 14

What are the solutions to the equation 4+3x^2=7 ?
The solutions to the equation 4+3x^2=7 are x=1,x=-1
Find the zeros of 4+3x^2=7
The zeros of 4+3x^2=7 are x=1,x=-1