What are the solutions to the equation roots x^2-6x+10 ?

The solutions to the equation roots x^2-6x+10 are x=3+i,x=3-i

Find the zeros of roots x^2-6x+10

The zeros of roots x^2-6x+10 are x=3+i,x=3-i

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roots

x^{2} - 6 x + 10

x = 3 + i, x = 3 - i

Solution steps

x^{2} - 6 x + 10

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 6 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 10 : 2 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 i}{2 \cdot 1} : 3 + i

x = \frac{- ( - 6 ) - 2 i}{2 \cdot 1} : 3 - i

The solutions to the quadratic equation are:

x = 3 + i, x = 3 - i

x^{2} - 36 = 0

19 + 2 x^{2} = 21

4 x^{2} + 6 x + 4 = 0

x^{2} - 2 x + 1

x^{2} + 2 x + 10

What are the solutions to the equation roots x^2-6x+10 ?
The solutions to the equation roots x^2-6x+10 are x=3+i,x=3-i
Find the zeros of roots x^2-6x+10
The zeros of roots x^2-6x+10 are x=3+i,x=3-i