What are the solutions to the equation roots x^2-2x+1 ?

The solutions to the equation roots x^2-2x+1 are x=1

Find the zeros of roots x^2-2x+1

The zeros of roots x^2-2x+1 are x=1

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roots

x^{2} - 2 x + 1

x = 1

Solution steps

x^{2} - 2 x + 1

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 2 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 2 )}{2 \cdot 1}

\frac{- ( - 2 )}{2 \cdot 1} = 1

x = 1

The solution to the quadratic equation is:

x = 1

x^{2} + 2 x + 10

14 + 3 x^{2} = 26

x, 3 x^{2} + 12 x = 0

x^{2}

6 x^{2} + 8 x + 9

What are the solutions to the equation roots x^2-2x+1 ?
The solutions to the equation roots x^2-2x+1 are x=1
Find the zeros of roots x^2-2x+1
The zeros of roots x^2-2x+1 are x=1