What are the solutions to the equation 1/5+((y-1)^2)/(10)=1 ?

The solutions to the equation 1/5+((y-1)^2)/(10)=1 are y=2sqrt(2)+1,y=-2sqrt(2)+1

Find the zeros of 1/5+((y-1)^2)/(10)=1

The zeros of 1/5+((y-1)^2)/(10)=1 are y=2sqrt(2)+1,y=-2sqrt(2)+1

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\frac{1}{5} + \frac{( y - 1 ) ^{2}}{10} = 1

y = 22 + 1, y = - 22 + 1

Solution steps

\frac{1}{5} + \frac{( y - 1 ) ^{2}}{10} = 1

Move

\frac{1}{5}

to the right side

\frac{( y - 1 ) ^{2}}{10} = 1 - \frac{1}{5}

Simplify

1 - \frac{1}{5} : \frac{4}{5}

\frac{( y - 1 ) ^{2}}{10} = \frac{4}{5}

Multiply both sides by

10

(y - 1)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 1 = 8 : y = 22 + 1

Solve

y - 1 = - 8 : y = - 22 + 1

The solutions to the quadratic equation are:

y = 22 + 1, y = - 22 + 1

\frac{\frac{x}{y} - 2}{y - x}

\frac{1 + 2 + 3 + 4 + 5}{2 + 4 + 6 + 8 + 10}

x (x - 1) = 12

(x - 4)^{2} + 4 = 36

\frac{1}{14.5} + \frac{1}{45.5} + \frac{1}{85.5}

What are the solutions to the equation 1/5+((y-1)^2)/(10)=1 ?
The solutions to the equation 1/5+((y-1)^2)/(10)=1 are y=2sqrt(2)+1,y=-2sqrt(2)+1
Find the zeros of 1/5+((y-1)^2)/(10)=1
The zeros of 1/5+((y-1)^2)/(10)=1 are y=2sqrt(2)+1,y=-2sqrt(2)+1