What are the solutions to the equation solvefor x,3x^2+12x=0 ?

The solutions to the equation solvefor x,3x^2+12x=0 are x=0,x=-4

Find the zeros of solvefor x,3x^2+12x=0

The zeros of solvefor x,3x^2+12x=0 are x=0,x=-4

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x, 3 x^{2} + 12 x = 0

x = 0, x = - 4

Solution steps

3 x^{2} + 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 \cdot 0 = 12

x_{1, 2} = \frac{- 12 \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 12}{2 \cdot 3}, x_{2} = \frac{- 12 - 12}{2 \cdot 3}

x = \frac{- 12 + 12}{2 \cdot 3} : 0

x = \frac{- 12 - 12}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

x^{2}

6 x^{2} + 8 x + 9

x, f = a (x - h)^{2} + k

s^{2} + 2 s + 5

5 x^{2} - 2 = - 92

What are the solutions to the equation solvefor x,3x^2+12x=0 ?
The solutions to the equation solvefor x,3x^2+12x=0 are x=0,x=-4
Find the zeros of solvefor x,3x^2+12x=0
The zeros of solvefor x,3x^2+12x=0 are x=0,x=-4