What are the solutions to the equation (x+4)^2-38=-22 ?

The solutions to the equation (x+4)^2-38=-22 are x=0,x=-8

Find the zeros of (x+4)^2-38=-22

The zeros of (x+4)^2-38=-22 are x=0,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 4)^{2} - 38 = - 22

x = 0, x = - 8

Solution steps

(x + 4)^{2} - 38 = - 22

Move

38

to the right side

(x + 4)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 16 : x = 0

Solve

x + 4 = - 16 : x = - 8

The solutions to the quadratic equation are:

x = 0, x = - 8

x^{2} + 9 = 3

y, x^{2} - 2 x y + y^{2} = 0

3 p^{2} + 11 p = 4

13 + 3 x^{2} = 16

3 (x^{2} - 2) - 1 = 5

What are the solutions to the equation (x+4)^2-38=-22 ?
The solutions to the equation (x+4)^2-38=-22 are x=0,x=-8
Find the zeros of (x+4)^2-38=-22
The zeros of (x+4)^2-38=-22 are x=0,x=-8