What are the solutions to the equation 4(x+7)^2+22=38 ?

The solutions to the equation 4(x+7)^2+22=38 are x=-5,x=-9

Find the zeros of 4(x+7)^2+22=38

The zeros of 4(x+7)^2+22=38 are x=-5,x=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (x + 7)^{2} + 22 = 38

x = - 5, x = - 9

Solution steps

4 (x + 7)^{2} + 22 = 38

Move

22

to the right side

4 (x + 7)^{2} = 16

Divide both sides by

4

(x + 7)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 4 : x = - 5

Solve

x + 7 = - 4 : x = - 9

The solutions to the quadratic equation are:

x = - 5, x = - 9

x^{2} - 2 x - 2 = 6

14 - 3 x^{2} = 8

4 (3 x - 8)^{2} = 27

s^{2} + s + 1

5 x^{2} - 30 x + 85 = 0

What are the solutions to the equation 4(x+7)^2+22=38 ?
The solutions to the equation 4(x+7)^2+22=38 are x=-5,x=-9
Find the zeros of 4(x+7)^2+22=38
The zeros of 4(x+7)^2+22=38 are x=-5,x=-9