What are the solutions to the equation 0=2x^2+6x-14 ?

The solutions to the equation 0=2x^2+6x-14 are x=(-3+sqrt(37))/2 ,x=-(3+sqrt(37))/2

Find the zeros of 0=2x^2+6x-14

The zeros of 0=2x^2+6x-14 are x=(-3+sqrt(37))/2 ,x=-(3+sqrt(37))/2

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0 = 2 x^{2} + 6 x - 14

x = \frac{- 3 + 37}{2}, x = - \frac{3 + 37}{2}

Decimal Notation

x = 1.54138 \dots, x = - 4.54138 \dots

Solution steps

0 = 2 x^{2} + 6 x - 14

Switch sides

2 x^{2} + 6 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 14) = 237

x_{1, 2} = \frac{- 6 \pm 2 37}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 37}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 37}{2 \cdot 2}

x = \frac{- 6 + 2 37}{2 \cdot 2} : \frac{- 3 + 37}{2}

x = \frac{- 6 - 2 37}{2 \cdot 2} : - \frac{3 + 37}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 37}{2}, x = - \frac{3 + 37}{2}

4 (x + 2)^{2} + 4 = 40

\frac{( 2 x ^{2} + 7 )}{3} = 13

n^{2} - 2 n + 4 = 0

x^{2} - 4

15 + 3 x^{2} = 24

What are the solutions to the equation 0=2x^2+6x-14 ?
The solutions to the equation 0=2x^2+6x-14 are x=(-3+sqrt(37))/2 ,x=-(3+sqrt(37))/2
Find the zeros of 0=2x^2+6x-14
The zeros of 0=2x^2+6x-14 are x=(-3+sqrt(37))/2 ,x=-(3+sqrt(37))/2