What are the solutions to the equation 3(x+5)^2=12 ?

The solutions to the equation 3(x+5)^2=12 are x=-3,x=-7

Find the zeros of 3(x+5)^2=12

The zeros of 3(x+5)^2=12 are x=-3,x=-7

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3 (x + 5)^{2} = 12

x = - 3, x = - 7

Solution steps

3 (x + 5)^{2} = 12

Divide both sides by

3

(x + 5)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 4 : x = - 3

Solve

x + 5 = - 4 : x = - 7

The solutions to the quadratic equation are:

x = - 3, x = - 7

y, x^{2} + x y + y^{2} = 0

- b^{2} + 7 \cdot b - 10 = 0

x^{2} + 2 x + 2 = 0

x^{2} = \frac{5.6}{2.45}

x^{2} - 64 = 0

What are the solutions to the equation 3(x+5)^2=12 ?
The solutions to the equation 3(x+5)^2=12 are x=-3,x=-7
Find the zeros of 3(x+5)^2=12
The zeros of 3(x+5)^2=12 are x=-3,x=-7