What are the solutions to the equation roots x^2-x-2 ?

The solutions to the equation roots x^2-x-2 are x=2,x=-1

Find the zeros of roots x^2-x-2

The zeros of roots x^2-x-2 are x=2,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

roots

x^{2} - x - 2

x = 2, x = - 1

Solution steps

x^{2} - x - 2

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

x = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

x^{2} - 16 = 0

x^{2} + x + 2

x^{2} - 10 x + 21 = x - 3

- 9 x = x^{2} + 14

x, 2 (cos x)^{2} - 4 s in x cos x = - 1

What are the solutions to the equation roots x^2-x-2 ?
The solutions to the equation roots x^2-x-2 are x=2,x=-1
Find the zeros of roots x^2-x-2
The zeros of roots x^2-x-2 are x=2,x=-1