What are the solutions to the equation roots x^2+x+2 ?

The solutions to the equation roots x^2+x+2 are x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

Find the zeros of roots x^2+x+2

The zeros of roots x^2+x+2 are x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2

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roots

x^{2} + x + 2

x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

Solution steps

x^{2} + x + 2

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 2 : 7 i

x_{1, 2} = \frac{- 1 \pm 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 7 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 7 i}{2 \cdot 1}

x = \frac{- 1 + 7 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{7}{2}

x = \frac{- 1 - 7 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{7}{2}, x = - \frac{1}{2} - i \frac{7}{2}

x^{2} - 10 x + 21 = x - 3

- 9 x = x^{2} + 14

x, 2 (cos x)^{2} - 4 s in x cos x = - 1

5 x^{2} + 7 x + 9 = 5 - 3 x

x^{2} + 6 x + 13

What are the solutions to the equation roots x^2+x+2 ?
The solutions to the equation roots x^2+x+2 are x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2
Find the zeros of roots x^2+x+2
The zeros of roots x^2+x+2 are x=-1/2+i(sqrt(7))/2 ,x=-1/2-i(sqrt(7))/2