What are the solutions to the equation roots x^2+6x+13 ?

The solutions to the equation roots x^2+6x+13 are x=-3+2i,x=-3-2i

Find the zeros of roots x^2+6x+13

The zeros of roots x^2+6x+13 are x=-3+2i,x=-3-2i

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roots

x^{2} + 6 x + 13

x = - 3 + 2 i, x = - 3 - 2 i

Solution steps

x^{2} + 6 x + 13

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 6 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 13 : 4 i

x_{1, 2} = \frac{- 6 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 i}{2 \cdot 1}

x = \frac{- 6 + 4 i}{2 \cdot 1} : - 3 + 2 i

x = \frac{- 6 - 4 i}{2 \cdot 1} : - 3 - 2 i

The solutions to the quadratic equation are:

x = - 3 + 2 i, x = - 3 - 2 i

(4 x - 5) (- x + 2) = 0

(5 x + 7)^{2} - (- 2 x + 5)^{2} = 0

x^{2} + 20 x + c

y, 4 x^{2} - 16 x + 4 y^{2} + 16 = 0

x^{2} - 5 x + \frac{4}{9} = 0

What are the solutions to the equation roots x^2+6x+13 ?
The solutions to the equation roots x^2+6x+13 are x=-3+2i,x=-3-2i
Find the zeros of roots x^2+6x+13
The zeros of roots x^2+6x+13 are x=-3+2i,x=-3-2i