What are the solutions to the equation roots x^2+20x+c ?

The solutions to the equation roots x^2+20x+c are x=-10+sqrt(-c+100),x=-sqrt(-c+100)-10

Find the zeros of roots x^2+20x+c

The zeros of roots x^2+20x+c are x=-10+sqrt(-c+100),x=-sqrt(-c+100)-10

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roots

x^{2} + 20 x + c

x = - 10 + - c + 100, x = - - c + 100 - 10

Solution steps

x^{2} + 20 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 20 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot c : 2 100 - c

x_{1, 2} = \frac{- 20 \pm 2 100 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 2 100 - c}{2 \cdot 1}, x_{2} = \frac{- 20 - 2 100 - c}{2 \cdot 1}

x = \frac{- 20 + 2 100 - c}{2 \cdot 1} : - 10 + - c + 100

x = \frac{- 20 - 2 100 - c}{2 \cdot 1} : - - c + 100 - 10

The solutions to the quadratic equation are:

x = - 10 + - c + 100, x = - - c + 100 - 10

y, 4 x^{2} - 16 x + 4 y^{2} + 16 = 0

x^{2} - 5 x + \frac{4}{9} = 0

2 (x + 4)^{2} + 15 = 17

x^{2} - 2 x - 2

2 x^{2} - 16 x + 33 = 0

What are the solutions to the equation roots x^2+20x+c ?
The solutions to the equation roots x^2+20x+c are x=-10+sqrt(-c+100),x=-sqrt(-c+100)-10
Find the zeros of roots x^2+20x+c
The zeros of roots x^2+20x+c are x=-10+sqrt(-c+100),x=-sqrt(-c+100)-10