What are the solutions to the equation 3(x-9)^2=27 ?

The solutions to the equation 3(x-9)^2=27 are x=12,x=6

Find the zeros of 3(x-9)^2=27

The zeros of 3(x-9)^2=27 are x=12,x=6

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3 (x - 9)^{2} = 27

x = 12, x = 6

Solution steps

3 (x - 9)^{2} = 27

Divide both sides by

3

(x - 9)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 9 = 9 : x = 12

Solve

x - 9 = - 9 : x = 6

The solutions to the quadratic equation are:

x = 12, x = 6

a^{3} + a + a^{2} + 1 + x^{2} + a^{2} x^{2}

k (k - 1) = 10

x^{2} + 4 x + 3

u, v^{2} = u^{2} + 2 a s

- 9 x^{2} = 30 x + 25

What are the solutions to the equation 3(x-9)^2=27 ?
The solutions to the equation 3(x-9)^2=27 are x=12,x=6
Find the zeros of 3(x-9)^2=27
The zeros of 3(x-9)^2=27 are x=12,x=6