What are the solutions to the equation roots x^2+2x+3 ?

The solutions to the equation roots x^2+2x+3 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

Find the zeros of roots x^2+2x+3

The zeros of roots x^2+2x+3 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

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roots

x^{2} + 2 x + 3

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

x^{2} + 2 x + 3

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

x_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

x = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

x = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

x^{2} + 16 x + c

(- 5 x + 3) (- x + 6) = 0

\frac{34 x ^{2}}{2 \cdot + 2.6} = 9.8 x

- 3 x^{2} - 18 x - 6 = 0

v, \frac{GM m}{r ^{2}} = m \frac{v ^{2}}{r}

What are the solutions to the equation roots x^2+2x+3 ?
The solutions to the equation roots x^2+2x+3 are x=-1+sqrt(2)i,x=-1-sqrt(2)i
Find the zeros of roots x^2+2x+3
The zeros of roots x^2+2x+3 are x=-1+sqrt(2)i,x=-1-sqrt(2)i