What are the solutions to the equation 4(x+2)^2=24 ?

The solutions to the equation 4(x+2)^2=24 are x=sqrt(6)-2,x=-sqrt(6)-2

Find the zeros of 4(x+2)^2=24

The zeros of 4(x+2)^2=24 are x=sqrt(6)-2,x=-sqrt(6)-2

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4 (x + 2)^{2} = 24

x = 6 - 2, x = - 6 - 2

Decimal Notation

x = 0.44948 \dots, x = - 4.44948 \dots

Solution steps

4 (x + 2)^{2} = 24

Divide both sides by

4

(x + 2)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 6 : x = 6 - 2

Solve

x + 2 = - 6 : x = - 6 - 2

The solutions to the quadratic equation are:

x = 6 - 2, x = - 6 - 2

x, 16 x^{2} + 9 = 5

14 + 2 x^{2} = 24

2 - 2 x^{2} = - 30

x^{2} + 14 x + c

4 (x^{2} - 8) + 3 = - 5

What are the solutions to the equation 4(x+2)^2=24 ?
The solutions to the equation 4(x+2)^2=24 are x=sqrt(6)-2,x=-sqrt(6)-2
Find the zeros of 4(x+2)^2=24
The zeros of 4(x+2)^2=24 are x=sqrt(6)-2,x=-sqrt(6)-2