What are the solutions to the equation roots s^2+8s+16 ?

The solutions to the equation roots s^2+8s+16 are s=-4

Find the zeros of roots s^2+8s+16

The zeros of roots s^2+8s+16 are s=-4

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roots

s^{2} + 8 s + 16

s = - 4

Solution steps

s^{2} + 8 s + 16

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 8 s + 16 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

s_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

s = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

s = - 4

The solution to the quadratic equation is:

s = - 4

x^{2} + 5 x + \frac{5}{4} = 0

36 + 6 x - 6 x^{2} = 0

2 (x - 3)^{2} - 5 = 13

2 x^{2} - 9 x + 11 = 0

0 = y^{2} + 6 y - 16

What are the solutions to the equation roots s^2+8s+16 ?
The solutions to the equation roots s^2+8s+16 are s=-4
Find the zeros of roots s^2+8s+16
The zeros of roots s^2+8s+16 are s=-4