What are the solutions to the equation 0=y^2+6y-16 ?

The solutions to the equation 0=y^2+6y-16 are y=2,y=-8

Find the zeros of 0=y^2+6y-16

The zeros of 0=y^2+6y-16 are y=2,y=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = y^{2} + 6 y - 16

y = 2, y = - 8

Solution steps

0 = y^{2} + 6 y - 16

Switch sides

y^{2} + 6 y - 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

y_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 10}{2 \cdot 1}, y_{2} = \frac{- 6 - 10}{2 \cdot 1}

y = \frac{- 6 + 10}{2 \cdot 1} : 2

y = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

y = 2, y = - 8

3 x^{2} - 6 x + 2

4 x^{2} + 3 x - 11 = 3 x - 2

x^{2} + 4 = 5

x (x + 5) = 4 (x + 5)

2 = - 3 x^{2} + 8

What are the solutions to the equation 0=y^2+6y-16 ?
The solutions to the equation 0=y^2+6y-16 are y=2,y=-8
Find the zeros of 0=y^2+6y-16
The zeros of 0=y^2+6y-16 are y=2,y=-8