What are the solutions to the equation roots 3x^2-6x+2 ?

The solutions to the equation roots 3x^2-6x+2 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

Find the zeros of roots 3x^2-6x+2

The zeros of roots 3x^2-6x+2 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

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roots

3 x^{2} - 6 x + 2

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

Solution steps

3 x^{2} - 6 x + 2

The roots are the intercepts with the x-axis

(y = 0)

3 x^{2} - 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 2 = 23

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 3}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 3}{2 \cdot 3} : \frac{3 + 3}{3}

x = \frac{- ( - 6 ) - 2 3}{2 \cdot 3} : \frac{3 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

4 x^{2} + 3 x - 11 = 3 x - 2

x^{2} + 4 = 5

x (x + 5) = 4 (x + 5)

2 = - 3 x^{2} + 8

x^{2} + 3 x + 2

What are the solutions to the equation roots 3x^2-6x+2 ?
The solutions to the equation roots 3x^2-6x+2 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3
Find the zeros of roots 3x^2-6x+2
The zeros of roots 3x^2-6x+2 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3