What are the solutions to the equation x(x+5)=4(x+5) ?

The solutions to the equation x(x+5)=4(x+5) are x=-5,x=4

Find the zeros of x(x+5)=4(x+5)

The zeros of x(x+5)=4(x+5) are x=-5,x=4

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x (x + 5) = 4 (x + 5)

x = - 5, x = 4

Solution steps

x (x + 5) = 4 (x + 5)

Move

4 (x + 5)

to the left side

x (x + 5) - 4 (x + 5) = 0

Factor

x (x + 5) - 4 (x + 5) : (x + 5) (x - 4)

(x + 5) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x - 4 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = - 5, x = 4

2 = - 3 x^{2} + 8

x^{2} + 3 x + 2

x^{2} - 19 x - 120 = 0

- 2 x^{2} + \frac{x}{3} + 4 = 0

(- x - 4) (3 x + 3) = 0

What are the solutions to the equation x(x+5)=4(x+5) ?
The solutions to the equation x(x+5)=4(x+5) are x=-5,x=4
Find the zeros of x(x+5)=4(x+5)
The zeros of x(x+5)=4(x+5) are x=-5,x=4