What are the solutions to the equation -x^2-8x+12=0 ?

The solutions to the equation -x^2-8x+12=0 are x=-2(2+sqrt(7)),x=2(sqrt(7)-2)

Find the zeros of -x^2-8x+12=0

The zeros of -x^2-8x+12=0 are x=-2(2+sqrt(7)),x=2(sqrt(7)-2)

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- x^{2} - 8 x + 12 = 0

x = - 2 (2 + 7), x = 2 (7 - 2)

Decimal Notation

x = - 9.29150 \dots, x = 1.29150 \dots

Solution steps

- x^{2} - 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 1 ) \cdot 12}{2 ( - 1 )}

(- 8)^{2} - 4 (- 1) \cdot 12 = 47

x_{1, 2} = \frac{- ( - 8 ) \pm 4 7}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 7}{2 ( - 1 )}, x_{2} = \frac{- ( - 8 ) - 4 7}{2 ( - 1 )}

x = \frac{- ( - 8 ) + 4 7}{2 ( - 1 )} : - 2 (2 + 7)

x = \frac{- ( - 8 ) - 4 7}{2 ( - 1 )} : 2 (7 - 2)

The solutions to the quadratic equation are:

x = - 2 (2 + 7), x = 2 (7 - 2)

81 x^{2} + 36 x + 4 = 0

3 x^{2} + 23 x + 15

4 - 3600 \cdot + x^{2} = 0

4 x^{2} - 1 = 0

t^{2} - 22 t + 9 = 0

What are the solutions to the equation -x^2-8x+12=0 ?
The solutions to the equation -x^2-8x+12=0 are x=-2(2+sqrt(7)),x=2(sqrt(7)-2)
Find the zeros of -x^2-8x+12=0
The zeros of -x^2-8x+12=0 are x=-2(2+sqrt(7)),x=2(sqrt(7)-2)