What are the solutions to the equation solvefor b,b^2-m^2=0 ?

The solutions to the equation solvefor b,b^2-m^2=0 are b=m,b=-m

Find the zeros of solvefor b,b^2-m^2=0

The zeros of solvefor b,b^2-m^2=0 are b=m,b=-m

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solve for

b, b^{2} - m^{2} = 0

b = m, b = - m

Solution steps

b^{2} - m^{2} = 0

Move

m^{2}

to the right side

b^{2} = m^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = m^{2}, b = - m^{2}

Simplify

m^{2} : m

Simplify

- m^{2} : - m

b = m, b = - m

4 x^{2} + 53 = 28 x

9 z^{2} - 27 z + 20 = 0

y, x^{2} + y^{2} - x y = 1

y, x^{2} + 2 x y - y^{2} + x = 36

\frac{x ^{2}}{2} - 4 x = 3 + \frac{x ^{2} - 12}{4}

What are the solutions to the equation solvefor b,b^2-m^2=0 ?
The solutions to the equation solvefor b,b^2-m^2=0 are b=m,b=-m
Find the zeros of solvefor b,b^2-m^2=0
The zeros of solvefor b,b^2-m^2=0 are b=m,b=-m