What are the solutions to the equation 9z^2-27z+20=0 ?

The solutions to the equation 9z^2-27z+20=0 are z= 5/3 ,z= 4/3

Find the zeros of 9z^2-27z+20=0

The zeros of 9z^2-27z+20=0 are z= 5/3 ,z= 4/3

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9 z^{2} - 27 z + 20 = 0

z = \frac{5}{3}, z = \frac{4}{3}

Decimal Notation

z = 1.66666 \dots, z = 1.33333 \dots

Solution steps

9 z^{2} - 27 z + 20 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 9 \cdot 20}{2 \cdot 9}

(- 27)^{2} - 4 \cdot 9 \cdot 20 = 3

z_{1, 2} = \frac{- ( - 27 ) \pm 3}{2 \cdot 9}

Separate the solutions

z_{1} = \frac{- ( - 27 ) + 3}{2 \cdot 9}, z_{2} = \frac{- ( - 27 ) - 3}{2 \cdot 9}

z = \frac{- ( - 27 ) + 3}{2 \cdot 9} : \frac{5}{3}

z = \frac{- ( - 27 ) - 3}{2 \cdot 9} : \frac{4}{3}

The solutions to the quadratic equation are:

z = \frac{5}{3}, z = \frac{4}{3}

y, x^{2} + y^{2} - x y = 1

y, x^{2} + 2 x y - y^{2} + x = 36

\frac{x ^{2}}{2} - 4 x = 3 + \frac{x ^{2} - 12}{4}

x^{2} - 100 = 0

x^{2} - 2 x - 28 = - 6 x + 4

What are the solutions to the equation 9z^2-27z+20=0 ?
The solutions to the equation 9z^2-27z+20=0 are z= 5/3 ,z= 4/3
Find the zeros of 9z^2-27z+20=0
The zeros of 9z^2-27z+20=0 are z= 5/3 ,z= 4/3