What are the solutions to the equation 4x^2+37=-20x ?

The solutions to the equation 4x^2+37=-20x are x=-5/2+sqrt(3)i,x=-5/2-sqrt(3)i

Find the zeros of 4x^2+37=-20x

The zeros of 4x^2+37=-20x are x=-5/2+sqrt(3)i,x=-5/2-sqrt(3)i

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4 x^{2} + 37 = - 20 x

x = - \frac{5}{2} + 3 i, x = - \frac{5}{2} - 3 i

Solution steps

4 x^{2} + 37 = - 20 x

Move

20 x

to the left side

4 x^{2} + 37 + 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 20 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 37}{2 \cdot 4}

Simplify

2 0^{2} - 4 \cdot 4 \cdot 37 : 83 i

x_{1, 2} = \frac{- 20 \pm 8 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 8 3 i}{2 \cdot 4}, x_{2} = \frac{- 20 - 8 3 i}{2 \cdot 4}

x = \frac{- 20 + 8 3 i}{2 \cdot 4} : - \frac{5}{2} + 3 i

x = \frac{- 20 - 8 3 i}{2 \cdot 4} : - \frac{5}{2} - 3 i

The solutions to the quadratic equation are:

x = - \frac{5}{2} + 3 i, x = - \frac{5}{2} - 3 i

x^{2} + x + 4

3 x^{2} - 5 x^{2} = 0

6 x^{2} + x = 222

h^{2} = 10 h - 3^{2}

x^{2} + 6 x + 8 = 0

What are the solutions to the equation 4x^2+37=-20x ?
The solutions to the equation 4x^2+37=-20x are x=-5/2+sqrt(3)i,x=-5/2-sqrt(3)i
Find the zeros of 4x^2+37=-20x
The zeros of 4x^2+37=-20x are x=-5/2+sqrt(3)i,x=-5/2-sqrt(3)i