What are the solutions to the equation 4x^2-3=-8x-6 ?

The solutions to the equation 4x^2-3=-8x-6 are x=-1/2 ,x=-3/2

Find the zeros of 4x^2-3=-8x-6

The zeros of 4x^2-3=-8x-6 are x=-1/2 ,x=-3/2

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4 x^{2} - 3 = - 8 x - 6

x = - \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = - 0.5, x = - 1.5

Solution steps

4 x^{2} - 3 = - 8 x - 6

Move

6

to the left side

4 x^{2} + 3 = - 8 x

Move

8 x

to the left side

4 x^{2} + 3 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 3 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 4}, x_{2} = \frac{- 8 - 4}{2 \cdot 4}

x = \frac{- 8 + 4}{2 \cdot 4} : - \frac{1}{2}

x = \frac{- 8 - 4}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{3}{2}

- 7000 x^{2} - 7280 x = 144551

x, z = x^{2} - y^{2}

x^{2} - 3 x - 130 = 0

x, \frac{x ^{2}}{a} + e = t

- 2 x^{2} + 13 x - 20 = 0

What are the solutions to the equation 4x^2-3=-8x-6 ?
The solutions to the equation 4x^2-3=-8x-6 are x=-1/2 ,x=-3/2
Find the zeros of 4x^2-3=-8x-6
The zeros of 4x^2-3=-8x-6 are x=-1/2 ,x=-3/2