What are the solutions to the equation roots x^2+25 ?

The solutions to the equation roots x^2+25 are x=5i,x=-5i

Find the zeros of roots x^2+25

The zeros of roots x^2+25 are x=5i,x=-5i

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roots

x^{2} + 25

x = 5 i, x = - 5 i

Solution steps

x^{2} + 25

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 25 = 0

Move

25

to the right side

x^{2} = - 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 25, x = - - 25

- 25 = 5 i

- - 25 = - 5 i

x = 5 i, x = - 5 i

3 x^{2} + 21 x - 24 = 0

4 (x - 6)^{2} = 36

y, 3 y^{2} = x (x - 1)^{2}

- x^{2} - 2 x + 11 = 0

2 x^{2} + 5 x + 18 = (x + 4)^{2}

What are the solutions to the equation roots x^2+25 ?
The solutions to the equation roots x^2+25 are x=5i,x=-5i
Find the zeros of roots x^2+25
The zeros of roots x^2+25 are x=5i,x=-5i