What are the solutions to the equation -x^2-2x+11=0 ?

The solutions to the equation -x^2-2x+11=0 are x=-1-2sqrt(3),x=2sqrt(3)-1

Find the zeros of -x^2-2x+11=0

The zeros of -x^2-2x+11=0 are x=-1-2sqrt(3),x=2sqrt(3)-1

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- x^{2} - 2 x + 11 = 0

x = - 1 - 23, x = 23 - 1

Decimal Notation

x = - 4.46410 \dots, x = 2.46410 \dots

Solution steps

- x^{2} - 2 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 11}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 11 = 43

x_{1, 2} = \frac{- ( - 2 ) \pm 4 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 3}{2 ( - 1 )}, x_{2} = \frac{- ( - 2 ) - 4 3}{2 ( - 1 )}

x = \frac{- ( - 2 ) + 4 3}{2 ( - 1 )} : - 1 - 23

x = \frac{- ( - 2 ) - 4 3}{2 ( - 1 )} : 23 - 1

The solutions to the quadratic equation are:

x = - 1 - 23, x = 23 - 1

2 x^{2} + 5 x + 18 = (x + 4)^{2}

0 = 4 x^{2} + 20 x + 25

x, 12320 = 160 x^{2} + 640 x

12 x^{2} - 13 x + 4 = 13 x^{2} - 5 x + 1

x^{2} + 5 x - 310 = 0

What are the solutions to the equation -x^2-2x+11=0 ?
The solutions to the equation -x^2-2x+11=0 are x=-1-2sqrt(3),x=2sqrt(3)-1
Find the zeros of -x^2-2x+11=0
The zeros of -x^2-2x+11=0 are x=-1-2sqrt(3),x=2sqrt(3)-1