What are the solutions to the equation 8t^2-26t+15=0 ?

The solutions to the equation 8t^2-26t+15=0 are t= 5/2 ,t= 3/4

Find the zeros of 8t^2-26t+15=0

The zeros of 8t^2-26t+15=0 are t= 5/2 ,t= 3/4

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8 t^{2} - 26 t + 15 = 0

t = \frac{5}{2}, t = \frac{3}{4}

Decimal Notation

t = 2.5, t = 0.75

Solution steps

8 t^{2} - 26 t + 15 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 8 \cdot 15}{2 \cdot 8}

(- 26)^{2} - 4 \cdot 8 \cdot 15 = 14

t_{1, 2} = \frac{- ( - 26 ) \pm 14}{2 \cdot 8}

Separate the solutions

t_{1} = \frac{- ( - 26 ) + 14}{2 \cdot 8}, t_{2} = \frac{- ( - 26 ) - 14}{2 \cdot 8}

t = \frac{- ( - 26 ) + 14}{2 \cdot 8} : \frac{5}{2}

t = \frac{- ( - 26 ) - 14}{2 \cdot 8} : \frac{3}{4}

The solutions to the quadratic equation are:

t = \frac{5}{2}, t = \frac{3}{4}

4 x^{2} - 4 x = - 13

4 w^{2} + 20 w + 25 = 0

3 x^{2} - 2 x + 4 = 5

x^{2} - (2 x - 21)^{2} = 144

8 x^{2} - 35 = - 18 x

What are the solutions to the equation 8t^2-26t+15=0 ?
The solutions to the equation 8t^2-26t+15=0 are t= 5/2 ,t= 3/4
Find the zeros of 8t^2-26t+15=0
The zeros of 8t^2-26t+15=0 are t= 5/2 ,t= 3/4