What are the solutions to the equation 81x^2+36x=-4 ?

The solutions to the equation 81x^2+36x=-4 are x=-2/9

Find the zeros of 81x^2+36x=-4

The zeros of 81x^2+36x=-4 are x=-2/9

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81 x^{2} + 36 x = - 4

x = - \frac{2}{9}

Decimal Notation

x = - 0.22222 \dots

Solution steps

81 x^{2} + 36 x = - 4

Move

4

to the left side

81 x^{2} + 36 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 81 \cdot 4}{2 \cdot 81}

3 6^{2} - 4 \cdot 81 \cdot 4 = 0

x_{1, 2} = \frac{- 36 \pm 0}{2 \cdot 81}

x = \frac{- 36}{2 \cdot 81}

\frac{- 36}{2 \cdot 81} = - \frac{2}{9}

x = - \frac{2}{9}

The solution to the quadratic equation is:

x = - \frac{2}{9}

x, m x^{2} + 6 x - 3 = 0

2 (x + 3)^{2} = 30

\frac{2}{5} (x + 3)^{2} = 5

0 = 5 x^{2} + 25 x - 65

10 x^{2} + 5 x = 5 x - 8

What are the solutions to the equation 81x^2+36x=-4 ?
The solutions to the equation 81x^2+36x=-4 are x=-2/9
Find the zeros of 81x^2+36x=-4
The zeros of 81x^2+36x=-4 are x=-2/9