What are the solutions to the equation roots s^2+2s+10 ?

The solutions to the equation roots s^2+2s+10 are s=-1+3i,s=-1-3i

Find the zeros of roots s^2+2s+10

The zeros of roots s^2+2s+10 are s=-1+3i,s=-1-3i

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roots

s^{2} + 2 s + 10

s = - 1 + 3 i, s = - 1 - 3 i

Solution steps

s^{2} + 2 s + 10

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + 2 s + 10 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 10 : 6 i

s_{1, 2} = \frac{- 2 \pm 6 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 6 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 6 i}{2 \cdot 1}

s = \frac{- 2 + 6 i}{2 \cdot 1} : - 1 + 3 i

s = \frac{- 2 - 6 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

s = - 1 + 3 i, s = - 1 - 3 i

4 x^{2} + 69 = 28 x

x^{2} - x - 35 = - x + 1

4 x^{2} - 16 x - 33

x^{2} - 2 x - 24 = 0

y, x y - 3 x + 4 x^{2} = 7

What are the solutions to the equation roots s^2+2s+10 ?
The solutions to the equation roots s^2+2s+10 are s=-1+3i,s=-1-3i
Find the zeros of roots s^2+2s+10
The zeros of roots s^2+2s+10 are s=-1+3i,s=-1-3i