What are the solutions to the equation 5(x+6)^2-48=-28 ?

The solutions to the equation 5(x+6)^2-48=-28 are x=-4,x=-8

Find the zeros of 5(x+6)^2-48=-28

The zeros of 5(x+6)^2-48=-28 are x=-4,x=-8

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5 (x + 6)^{2} - 48 = - 28

x = - 4, x = - 8

Solution steps

5 (x + 6)^{2} - 48 = - 28

Move

48

to the right side

5 (x + 6)^{2} = 20

Divide both sides by

5

(x + 6)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 6 = 4 : x = - 4

Solve

x + 6 = - 4 : x = - 8

The solutions to the quadratic equation are:

x = - 4, x = - 8

- 3 x^{2} - 21 x - 30 = 0

d^{2} - 9 d + 2 = 0

x^{2} + 5 x = 0

3 (x + 1)^{2} - 6 = 141

3 m^{2} - 4 m - 4 = m

What are the solutions to the equation 5(x+6)^2-48=-28 ?
The solutions to the equation 5(x+6)^2-48=-28 are x=-4,x=-8
Find the zeros of 5(x+6)^2-48=-28
The zeros of 5(x+6)^2-48=-28 are x=-4,x=-8