What are the solutions to the equation d^2-9d+2=0 ?

The solutions to the equation d^2-9d+2=0 are d=(9+sqrt(73))/2 ,d=(9-sqrt(73))/2

Find the zeros of d^2-9d+2=0

The zeros of d^2-9d+2=0 are d=(9+sqrt(73))/2 ,d=(9-sqrt(73))/2

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d^{2} - 9 d + 2 = 0

d = \frac{9 + 73}{2}, d = \frac{9 - 73}{2}

Decimal Notation

d = 8.77200 \dots, d = 0.22799 \dots

Solution steps

d^{2} - 9 d + 2 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 2 = 73

d_{1, 2} = \frac{- ( - 9 ) \pm 73}{2 \cdot 1}

Separate the solutions

d_{1} = \frac{- ( - 9 ) + 73}{2 \cdot 1}, d_{2} = \frac{- ( - 9 ) - 73}{2 \cdot 1}

d = \frac{- ( - 9 ) + 73}{2 \cdot 1} : \frac{9 + 73}{2}

d = \frac{- ( - 9 ) - 73}{2 \cdot 1} : \frac{9 - 73}{2}

The solutions to the quadratic equation are:

d = \frac{9 + 73}{2}, d = \frac{9 - 73}{2}

x^{2} + 5 x = 0

3 (x + 1)^{2} - 6 = 141

3 m^{2} - 4 m - 4 = m

4 x^{2} + 100 = 2 x^{2} + 492

y, 36 x^{2} + 36 y^{2} + 48 x - 108 y + 97 = 0

What are the solutions to the equation d^2-9d+2=0 ?
The solutions to the equation d^2-9d+2=0 are d=(9+sqrt(73))/2 ,d=(9-sqrt(73))/2
Find the zeros of d^2-9d+2=0
The zeros of d^2-9d+2=0 are d=(9+sqrt(73))/2 ,d=(9-sqrt(73))/2