What are the solutions to the equation 4x^2+100=2x^2+492 ?

The solutions to the equation 4x^2+100=2x^2+492 are x=14,x=-14

Find the zeros of 4x^2+100=2x^2+492

The zeros of 4x^2+100=2x^2+492 are x=14,x=-14

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4 x^{2} + 100 = 2 x^{2} + 492

x = 14, x = - 14

Solution steps

4 x^{2} + 100 = 2 x^{2} + 492

Move

100

to the right side

4 x^{2} = 2 x^{2} + 392

Move

2 x^{2}

to the left side

2 x^{2} = 392

Divide both sides by

2

x^{2} = 196

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 196, x = - 196

196 = 14

- 196 = - 14

x = 14, x = - 14

y, 36 x^{2} + 36 y^{2} + 48 x - 108 y + 97 = 0

y, x^{2} - x y - y^{2} = 1

x^{2} + 7 x + 3 = 3

x^{2} + 20 x = - 172

9 x^{2} = 54 x

What are the solutions to the equation 4x^2+100=2x^2+492 ?
The solutions to the equation 4x^2+100=2x^2+492 are x=14,x=-14
Find the zeros of 4x^2+100=2x^2+492
The zeros of 4x^2+100=2x^2+492 are x=14,x=-14