What are the solutions to the equation 2(x-8)^2-35=7 ?

The solutions to the equation 2(x-8)^2-35=7 are x=sqrt(21)+8,x=-sqrt(21)+8

Find the zeros of 2(x-8)^2-35=7

The zeros of 2(x-8)^2-35=7 are x=sqrt(21)+8,x=-sqrt(21)+8

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2 (x - 8)^{2} - 35 = 7

x = 21 + 8, x = - 21 + 8

Decimal Notation

x = 12.58257 \dots, x = 3.41742 \dots

Solution steps

2 (x - 8)^{2} - 35 = 7

Move

35

to the right side

2 (x - 8)^{2} = 42

Divide both sides by

2

(x - 8)^{2} = 21

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 8 = 21 : x = 21 + 8

Solve

x - 8 = - 21 : x = - 21 + 8

The solutions to the quadratic equation are:

x = 21 + 8, x = - 21 + 8

x^{2} - 5 x + 6 = 0

w, 30 w = 9 w^{2} + 25

d x^{2}

3 (x^{2} - 2) - 1 = 5

x^{2} + 3 x - 35 = 3 x + 1

What are the solutions to the equation 2(x-8)^2-35=7 ?
The solutions to the equation 2(x-8)^2-35=7 are x=sqrt(21)+8,x=-sqrt(21)+8
Find the zeros of 2(x-8)^2-35=7
The zeros of 2(x-8)^2-35=7 are x=sqrt(21)+8,x=-sqrt(21)+8