What are the solutions to the equation (x-1)^2-12=26 ?

The solutions to the equation (x-1)^2-12=26 are x=sqrt(38)+1,x=-sqrt(38)+1

Find the zeros of (x-1)^2-12=26

The zeros of (x-1)^2-12=26 are x=sqrt(38)+1,x=-sqrt(38)+1

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(x - 1)^{2} - 12 = 26

x = 38 + 1, x = - 38 + 1

Decimal Notation

x = 7.16441 \dots, x = - 5.16441 \dots

Solution steps

(x - 1)^{2} - 12 = 26

Move

12

to the right side

(x - 1)^{2} = 38

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 38 : x = 38 + 1

Solve

x - 1 = - 38 : x = - 38 + 1

The solutions to the quadratic equation are:

x = 38 + 1, x = - 38 + 1

x^{2} - 4 x = 4 x

80 x^{2} = - 16

5 x^{2} - 40 x = - 60

x^{2} - 3 x - 10 = 0

x^{2} + 1.2 x + 1

What are the solutions to the equation (x-1)^2-12=26 ?
The solutions to the equation (x-1)^2-12=26 are x=sqrt(38)+1,x=-sqrt(38)+1
Find the zeros of (x-1)^2-12=26
The zeros of (x-1)^2-12=26 are x=sqrt(38)+1,x=-sqrt(38)+1