What are the solutions to the equation 4x^2-12x+9=2x^2+4x+2 ?

The solutions to the equation 4x^2-12x+9=2x^2+4x+2 are x=(8+5sqrt(2))/2 ,x=(8-5sqrt(2))/2

Find the zeros of 4x^2-12x+9=2x^2+4x+2

The zeros of 4x^2-12x+9=2x^2+4x+2 are x=(8+5sqrt(2))/2 ,x=(8-5sqrt(2))/2

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4 x^{2} - 12 x + 9 = 2 x^{2} + 4 x + 2

x = \frac{8 + 5 2}{2}, x = \frac{8 - 5 2}{2}

Decimal Notation

x = 7.53553 \dots, x = 0.46446 \dots

Solution steps

4 x^{2} - 12 x + 9 = 2 x^{2} + 4 x + 2

Move

2

to the left side

4 x^{2} - 12 x + 7 = 2 x^{2} + 4 x

Move

4 x

to the left side

4 x^{2} - 16 x + 7 = 2 x^{2}

Move

2 x^{2}

to the left side

2 x^{2} - 16 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

(- 16)^{2} - 4 \cdot 2 \cdot 7 = 102

x_{1, 2} = \frac{- ( - 16 ) \pm 10 2}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 10 2}{2 \cdot 2}, x_{2} = \frac{- ( - 16 ) - 10 2}{2 \cdot 2}

x = \frac{- ( - 16 ) + 10 2}{2 \cdot 2} : \frac{8 + 5 2}{2}

x = \frac{- ( - 16 ) - 10 2}{2 \cdot 2} : \frac{8 - 5 2}{2}

The solutions to the quadratic equation are:

x = \frac{8 + 5 2}{2}, x = \frac{8 - 5 2}{2}

9 x^{2} - 12 x = - 4

x, x^{2} + y^{2} + z^{2} = 25

- 3 x^{2} + x + 4 = 0

12 - 2 x^{2} = - 20

(x - 3)^{2} + (3 x - 2) - 11 = 0

What are the solutions to the equation 4x^2-12x+9=2x^2+4x+2 ?
The solutions to the equation 4x^2-12x+9=2x^2+4x+2 are x=(8+5sqrt(2))/2 ,x=(8-5sqrt(2))/2
Find the zeros of 4x^2-12x+9=2x^2+4x+2
The zeros of 4x^2-12x+9=2x^2+4x+2 are x=(8+5sqrt(2))/2 ,x=(8-5sqrt(2))/2