What are the solutions to the equation -3x^2+x+4=0 ?

The solutions to the equation -3x^2+x+4=0 are x=-1,x= 4/3

Find the zeros of -3x^2+x+4=0

The zeros of -3x^2+x+4=0 are x=-1,x= 4/3

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- 3 x^{2} + x + 4 = 0

x = - 1, x = \frac{4}{3}

Decimal Notation

x = - 1, x = 1.33333 \dots

Solution steps

- 3 x^{2} + x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) \cdot 4}{2 ( - 3 )}

1^{2} - 4 (- 3) \cdot 4 = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 ( - 3 )}, x_{2} = \frac{- 1 - 7}{2 ( - 3 )}

x = \frac{- 1 + 7}{2 ( - 3 )} : - 1

x = \frac{- 1 - 7}{2 ( - 3 )} : \frac{4}{3}

The solutions to the quadratic equation are:

x = - 1, x = \frac{4}{3}

12 - 2 x^{2} = - 20

(x - 3)^{2} + (3 x - 2) - 11 = 0

2 (x + 9)^{2} - 29 = 33

x^{2} - 5 x + \frac{5}{4} = 0

4 x^{2} + 57 = - 28 x

What are the solutions to the equation -3x^2+x+4=0 ?
The solutions to the equation -3x^2+x+4=0 are x=-1,x= 4/3
Find the zeros of -3x^2+x+4=0
The zeros of -3x^2+x+4=0 are x=-1,x= 4/3