What are the solutions to the equation 4x^2-2=7x ?

The solutions to the equation 4x^2-2=7x are x=2,x=-1/4

Find the zeros of 4x^2-2=7x

The zeros of 4x^2-2=7x are x=2,x=-1/4

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4 x^{2} - 2 = 7 x

x = 2, x = - \frac{1}{4}

Solution steps

4 x^{2} - 2 = 7 x

Move

7 x

to the left side

4 x^{2} - 2 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 (- 2) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 4}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 4}

x = \frac{- ( - 7 ) + 9}{2 \cdot 4} : 2

x = \frac{- ( - 7 ) - 9}{2 \cdot 4} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{1}{4}

x (11 x + 4) = 36

9^{2} + 1 1^{2} = x^{2}

3 x^{2} - 3 x - 6 = 0

2 x + 1 = 5 x + 1 - 3 x

∣ 2 x + 5 ∣ = 3

What are the solutions to the equation 4x^2-2=7x ?
The solutions to the equation 4x^2-2=7x are x=2,x=-1/4
Find the zeros of 4x^2-2=7x
The zeros of 4x^2-2=7x are x=2,x=-1/4