What are the solutions to the equation 5(x+10)^2-24=26 ?

The solutions to the equation 5(x+10)^2-24=26 are x=sqrt(10)-10,x=-sqrt(10)-10

Find the zeros of 5(x+10)^2-24=26

The zeros of 5(x+10)^2-24=26 are x=sqrt(10)-10,x=-sqrt(10)-10

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5 (x + 10)^{2} - 24 = 26

x = 10 - 10, x = - 10 - 10

Decimal Notation

x = - 6.83772 \dots, x = - 13.16227 \dots

Solution steps

5 (x + 10)^{2} - 24 = 26

Move

24

to the right side

5 (x + 10)^{2} = 50

Divide both sides by

5

(x + 10)^{2} = 10

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 10 = 10 : x = 10 - 10

Solve

x + 10 = - 10 : x = - 10 - 10

The solutions to the quadratic equation are:

x = 10 - 10, x = - 10 - 10

(3 x - 1)^{2} = 9 x + 3

x^{2} + 20 x = - 75

4 z^{2} - 4 z - 15 = 0

x^{2} + 7 x = x

2 x^{2} + 4 = 8 x

What are the solutions to the equation 5(x+10)^2-24=26 ?
The solutions to the equation 5(x+10)^2-24=26 are x=sqrt(10)-10,x=-sqrt(10)-10
Find the zeros of 5(x+10)^2-24=26
The zeros of 5(x+10)^2-24=26 are x=sqrt(10)-10,x=-sqrt(10)-10