What are the solutions to the equation roots x^2-x ?

The solutions to the equation roots x^2-x are x=1,x=0

Find the zeros of roots x^2-x

The zeros of roots x^2-x are x=1,x=0

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roots

x^{2} - x

x = 1, x = 0

Solution steps

x^{2} - x

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

2 (x^{2} - 9) + 1 = 1

9 x^{2} + 36 x + 40 = 0

\frac{1}{2} x^{2} - 10 = \frac{3}{2} x^{2}

114.7 + 12.8 t - \frac{9.8 t ^{2}}{2} = 0

y^{2} = 15 y - 36

What are the solutions to the equation roots x^2-x ?
The solutions to the equation roots x^2-x are x=1,x=0
Find the zeros of roots x^2-x
The zeros of roots x^2-x are x=1,x=0