What are the solutions to the equation 10x^2-8x-8=0 ?

The solutions to the equation 10x^2-8x-8=0 are x=(2(1+sqrt(6)))/5 ,x=(2(1-sqrt(6)))/5

Find the zeros of 10x^2-8x-8=0

The zeros of 10x^2-8x-8=0 are x=(2(1+sqrt(6)))/5 ,x=(2(1-sqrt(6)))/5

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10 x^{2} - 8 x - 8 = 0

x = \frac{2 ( 1 + 6 )}{5}, x = \frac{2 ( 1 - 6 )}{5}

Decimal Notation

x = 1.37979 \dots, x = - 0.57979 \dots

Solution steps

10 x^{2} - 8 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 10 ( - 8 )}{2 \cdot 10}

(- 8)^{2} - 4 \cdot 10 (- 8) = 86

x_{1, 2} = \frac{- ( - 8 ) \pm 8 6}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 6}{2 \cdot 10}, x_{2} = \frac{- ( - 8 ) - 8 6}{2 \cdot 10}

x = \frac{- ( - 8 ) + 8 6}{2 \cdot 10} : \frac{2 ( 1 + 6 )}{5}

x = \frac{- ( - 8 ) - 8 6}{2 \cdot 10} : \frac{2 ( 1 - 6 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 1 + 6 )}{5}, x = \frac{2 ( 1 - 6 )}{5}

4 x^{2} + 61 = 28 x

4 x^{2} + 69 = 36 x

6 (x - 3)^{2} - 6 = 0

y, x^{2} + 2 x y + y^{2} = 0

- 4 x^{2} - 24 x - 36 = 0

What are the solutions to the equation 10x^2-8x-8=0 ?
The solutions to the equation 10x^2-8x-8=0 are x=(2(1+sqrt(6)))/5 ,x=(2(1-sqrt(6)))/5
Find the zeros of 10x^2-8x-8=0
The zeros of 10x^2-8x-8=0 are x=(2(1+sqrt(6)))/5 ,x=(2(1-sqrt(6)))/5