What are the solutions to the equation x^2+52=-12x ?

The solutions to the equation x^2+52=-12x are x=-6+4i,x=-6-4i

Find the zeros of x^2+52=-12x

The zeros of x^2+52=-12x are x=-6+4i,x=-6-4i

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x^{2} + 52 = - 12 x

x = - 6 + 4 i, x = - 6 - 4 i

Solution steps

x^{2} + 52 = - 12 x

Move

12 x

to the left side

x^{2} + 52 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 12 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 52}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 52 : 8 i

x_{1, 2} = \frac{- 12 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 8 i}{2 \cdot 1}

x = \frac{- 12 + 8 i}{2 \cdot 1} : - 6 + 4 i

x = \frac{- 12 - 8 i}{2 \cdot 1} : - 6 - 4 i

The solutions to the quadratic equation are:

x = - 6 + 4 i, x = - 6 - 4 i

5 (x^{2} - 4) - 5 = - 5

y, x^{2} y^{2} = 1

x^{2} + 2 x + a

x, x^{2} + y^{2} + z^{2} = 9

x^{2} + 12 x + 20 = 0

What are the solutions to the equation x^2+52=-12x ?
The solutions to the equation x^2+52=-12x are x=-6+4i,x=-6-4i
Find the zeros of x^2+52=-12x
The zeros of x^2+52=-12x are x=-6+4i,x=-6-4i