What are the solutions to the equation (2t^2)/3 = 8/3 pi^2 ?

The solutions to the equation (2t^2)/3 = 8/3 pi^2 are t=2pi,t=-2pi

Find the zeros of (2t^2)/3 = 8/3 pi^2

The zeros of (2t^2)/3 = 8/3 pi^2 are t=2pi,t=-2pi

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\frac{2 t ^{2}}{3} = \frac{8}{3} π^{2}

t = 2 π, t = - 2 π

Decimal Notation

t = 6.28318 \dots, t = - 6.28318 \dots

Solution steps

\frac{2 t ^{2}}{3} = \frac{8}{3} π^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{2 t ^{2}}{3} = \frac{8 π ^{2}}{3}

Multiply both sides by

3

2 t^{2} = 8 π^{2}

Divide both sides by

2

t^{2} = 4 π^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 4 π^{2}, t = - 4 π^{2}

4 π^{2} = 2 π

- 4 π^{2} = - 2 π

t = 2 π, t = - 2 π

\frac{1}{2} a^{2} - a - \frac{5}{2} = 0

y, x^{2} y - x^{2} + 4 y = 0

25 b^{2} + 24 b + 9 = - 6 b

5 x^{2} - 31 x - 28 = 0

5 k^{2} - 28 k + 19 = 4

What are the solutions to the equation (2t^2)/3 = 8/3 pi^2 ?
The solutions to the equation (2t^2)/3 = 8/3 pi^2 are t=2pi,t=-2pi
Find the zeros of (2t^2)/3 = 8/3 pi^2
The zeros of (2t^2)/3 = 8/3 pi^2 are t=2pi,t=-2pi