What are the solutions to the equation 25b^2+24b+9=-6b ?

The solutions to the equation 25b^2+24b+9=-6b are b=-3/5

Find the zeros of 25b^2+24b+9=-6b

The zeros of 25b^2+24b+9=-6b are b=-3/5

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25 b^{2} + 24 b + 9 = - 6 b

b = - \frac{3}{5}

Decimal Notation

b = - 0.6

Solution steps

25 b^{2} + 24 b + 9 = - 6 b

Move

6 b

to the left side

25 b^{2} + 30 b + 9 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 25 \cdot 9}{2 \cdot 25}

3 0^{2} - 4 \cdot 25 \cdot 9 = 0

b_{1, 2} = \frac{- 30 \pm 0}{2 \cdot 25}

b = \frac{- 30}{2 \cdot 25}

\frac{- 30}{2 \cdot 25} = - \frac{3}{5}

b = - \frac{3}{5}

The solution to the quadratic equation is:

b = - \frac{3}{5}

5 x^{2} - 31 x - 28 = 0

5 k^{2} - 28 k + 19 = 4

x^{2} + 2 x - 13 = 130

- 4 x^{2} - 24 x + 64 = 0

x^{2} - 11 x + 10 = 0

What are the solutions to the equation 25b^2+24b+9=-6b ?
The solutions to the equation 25b^2+24b+9=-6b are b=-3/5
Find the zeros of 25b^2+24b+9=-6b
The zeros of 25b^2+24b+9=-6b are b=-3/5